JML Institute Online 
AUTOMOTIVE ELECTRONICS:
(LAB EXPERIMENTS ON BOTTOM OF THIS SHEET.)
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(HINT):    10*sin(-48.54 degrees) + 10*cos(-48.54 degrees) = 6.62 - j7.5 + 7.33  + j3.2

LAB#2: EXPERIMENT
The currents here, due the the AC components are either leading or lagging the voltages.  This means that the phase angles are different,  so the calculation of IT must done by adding the x and y values of I1 and I2 vectorially.	
		
The currents in this lab must be added vectorially.  

	I1 = 650/Zb
	I2 = 650/Za
	ITx = I1*(R1/Za) + I2*(R2/Zb) 
	ITy = -I1*(XL/Za) + I2*(XC/Zb)
	Ivec = (ITx)^2+(ITy)^2
	IT = (Ivec)**1/2		hint:(square root)
	ZT = 650/IT
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